The function
f(x)=18000(0.52)x
 represents the value in dollars of a vehicle x years after it has been purchased new.
What is the average rate of change in value per year between years 4 and 8?
 


​​
−$18000/year

​​
−$1219.87/year


−$304.97/year

−$0.52/year

Respuesta :

Answer: −$304.97/year


Step-by-step explanation:

We know that the rate of change of function=[tex]\frac{f(x_2)-f(x_1)}{x_2-x_1}[/tex]

Thus, for the required situation the rate of change of function per year between years 4 and 8=

[tex]\frac{f(8)-f(4)}{8-4}\\\\=\frac{18000(0.52)^8-18000(0.52)^4}{4}\\\\=\frac{18000[(0.52)^8-(0.52)^4]}{4}\\\\=\frac{18000[0.00534-0.07311]}{4}\\\\=\frac{18000\times-0.06777}{4}\\\\=\frac{-1219.86}{4}=-304.97[/tex]

Hence the average rate of change in value per year between years 4 and 8= -$304.97 per year.

Answer:

304.97/year

Step-by-step explanation

We know that the rate of change of function=

Thus, for the required situation the rate of change of function per year between years 4 and 8=

Hence the average rate of change in value per year between years 4 and 8= -$304.97 per year.