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< CAD = 100....if u add < ACB + < CBA u get < CAD
================
< DAB = 125 and < ACB = 30

if DAB = 125.....then BAC = 180 - 125 = 55
and all 3 interior angles of a triangle = 180
< BAC + < ACB + < ABC = 180
55 + 30 + < ABC = 180
85 + < ABC = 180
< ABC = 180 - 85
< ABC = 95 <===

Answer:(1) The value of angle CAD is 100 degree. (2) The value of angle ABC is 95 degree.

Explanation:

(1)

According to the first given figure It is noticed that the value of angle ACB is 80 and angle ABC is 20 degree and we have to find angle CAD.

The exterior angle theorem of a triangle states that value of exterior angle is the sum of the other two interior angles.

[tex]\angle CAD=\angle ABC+\angle ACB[/tex]

[tex]\angle CAD=20+80=100[/tex]

Therefore, the angle CAD is 100 degree.

(2)

For second figure it is given that The measure of ∠DAB equals 125º. The measure of ∠ACB equals 30º.

By using the exterior angle theorem of a triangle, we can say that,

[tex]\angle BAD=\angle ABC+\angle ACB[/tex]

[tex]125=\angle ABC+30[/tex]

[tex]\angle ABC=125-30[/tex]

[tex]\angle ABC=95[/tex]

Therefore, the angle ABC is 95 degree.

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