The answer is D.
√-6(√-4 - √3) =
√-6 = √-1√6 = i√6 Express √-6 in terms of i
i√6(√-4 - √3)
√-4 = √-1√4 = i √4 Express √-4 in terms of i
i√6(i√4 - √3)
√4 = 2 simplify radicals
i√6(2i - √3)
√6(2i - √3) = 2i√6 - 3√2 Distribute √6 over 2i-√3
i(2i√6 - 3√2)
i(2i√6 - 3√2) = -3i√2-2√6 Distribute i over (2i)√6 - 3√2
-3i√2 - 2√6
factor -1 from -3i√2 - 2√6
= -(2√6 + 3i√2) == -2√6 - 3i√2
hope that helps!
