Answer:
The molar concentration of the unknown HCl is 2.5 M.
Explanation:
[tex]HCl+NaOH\rightarrow H_2O+NaCl[/tex]
Moles of NaOH in 25 mL of 2.0 M solution = n
[tex]2.0 mol/L=\frac{n}{0.025 L}[/tex]
n = 0.05 moles
According to reaction 1 mol of NaOH reacts with 1 mol of HCl then 0.05 mol of NaOH will react with 0.05 moles of HCl.
Molar concentration of the unknown HCl solution.
[tex}M=\frac{\text{Number of moles of HCl}}{\text{Volume of solution in L}}[/tex]
[tex]M=\frac{0.05 mol}{0.020 L}=2.5 mol/L[/tex]
The molar concentration of the unknown HCl is 2.5 M.
