Respuesta :
The reaction between calcium carbonate and hydrochloric acid can be expressed through the chemical reaction,
CaCO3 + 2HCl --> CaCl2 + H2O + CO2
The molecular weight of calcium carbonate is 100 g/mol while that of hydrochloric acid is 36.45. The equation above depicts that 100 g of calcium carbonate can be dissolved in 72.9 g of hydrochloric acid.
x = (4 g HCl)(100 g CaCO3 / 72.9 HCl)
x = 5.49 g
Answer: 5.49 g
CaCO3 + 2HCl --> CaCl2 + H2O + CO2
The molecular weight of calcium carbonate is 100 g/mol while that of hydrochloric acid is 36.45. The equation above depicts that 100 g of calcium carbonate can be dissolved in 72.9 g of hydrochloric acid.
x = (4 g HCl)(100 g CaCO3 / 72.9 HCl)
x = 5.49 g
Answer: 5.49 g
Answer:
4 grams of HCl need 5.486 grams of CaCO3
Explanation:
The balanced chemical reaction between hydrocloric acid and calcium carbonate can be expressed as
CaCO3+ 2HCl -> CaCl2 + CO2 + H2O
This means that 1 mole of CaCO3 reacts with 2 mole of HCl to produce 1 mole of CaCl2,CO2 and H2O.
2 mole of HCl needs 2 mole of CaCO3
In term of mass we can write that
72.9 grams of HCl need 100 grams of CaCO3
1 grams of HCl need (100/72.9) grams of CaCO3
4 grams of HCl need ((100*4)/72.9) grams of CaCO3
4 grams of HCl need 5.486 grams of CaCO3