A jar contains only one blue tile, one green tile, one red tile, and one yellow tile. if a tile is chosen at random and then replaced in the jar, and then a second tile is chosen at random, how many of the possible outcomes contain at least one red tile?

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laikensbaconp0zj0f laikensbaconp0zj0f · Answer 1 · 2018-06-25T14:57:54+02:00

its 7 just had the test

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throwdolbeau throwdolbeau · Answer 2 · 2019-02-28T07:10:47+01:00

Answer:

Possible outcomes that contain at least one red tile = 7

Step-by-step explanation:

Number of blue tile = 1

Number of green tile = 1

Number of red tile = 1

Number of yellow tile = 1

Total number of tiles = 4

Possible number of outcomes in choosing one tile = 4

Possible number of outcomes in selecting the second tile = 4

⇒ Possible number of outcomes in selecting both the tiles = 4 × 4 = 16

We need to find the find the possible outcomes that contain atleast one red ⇒ One tile must be atleast of red color.

Now, Possible outcomes of selecting first tile if not red = 3

Possible outcomes of selecting second tile if not red = 3

⇒ Possible outcomes of selecting both the tiles if not red = 3 × 3 = 9

Hence, Possible outcomes that contain at least one red tile = 16 - 9 = 7