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A beam of red light is made to pass through two slits that are 3.55 E-3 meters apart. On a screen 2.25 meters away from the slits, an interference pattern appears with bands of light separated by 1.25 E-4 meters. What is the wavelength of the light?

1.97E-7m
0.197m
9.98E.7m
5.07E6m

Respuesta :

I am assuming you know the relation obtained between slit width, distance of screen from slits, distance of interference pattern obtained on the screen from the center and the wavelength of monochromatic light used in Young's Double Slit experiment.
λ =[tex] \frac{y*d}{D} = \frac{3.55*10^{-3}*1.25*10^{-4} }{2.25} = 1.97*10^{-7} m[/tex]
λ ~ 1.97 ×10⁻⁷m
okpalawalter8

The wavelength of the light is mathematically given as

lambda= 1.97*10^{-7} m

Option A is correct

What is the wavelength of the light?

Question Parameter(s):

A beam of red light is made to pass through two slits that are 3.55 E-3 meters apart.

an interference pattern appears with bands of light separated by 1.25 E-4 meters

Generally, the equation for the Wavelenght   is mathematically given as

[tex]\lambda=\frac{y*d}{D}[/tex]

Therefore

[tex]\lambda= \frac{3.55*10^{-3}*1.25*10^{-4} }{2.25}[/tex]

lambda= 1.97*10^{-7} m

In conclusion, the wavelength

lambda= 1.97*10^{-7} m

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