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[tex]rx + qx - d = gc \\rx + qx = d + gc \\x(r) + x(q) = d + gc \\x(r + q) = d + gc \\\frac{x(r + q)}{r + q} = \frac{d + gc}{r + q} \\x = \frac{d + gc}{r + q}[/tex]

When solving for x in rx + qx - d = gc, the solution is;

x = (gc + d)/(r + q)

This is about change in subject of formula in algebra.

We are given;

rx + qx - d = gc

We want to make x the subject of the formula.

Thus;

First step; Using addition property of equality, add d to both sides of the given equation to get;

rx + qx - d + d = gc + d

rx + qx = gc + d

Second Step; Factorize x out on the left hand side to obtain;

x(r + q) = gc + d

Third step; Using division property of equality, divide both sides by (r + q).

x(r + q)/(r + q) = (gc + d)/(r + q)

x = (gc + d)/(r + q)

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