Answer:
[tex]t_{1/2} = 0.25 hours[/tex]
Explanation:
As we know that
[tex]N = N_o e^{-\lambda t}[/tex]
here we know that
[tex]\lambda = \frac{ln2}{t_{1/2}}[/tex]
so we will have
[tex]N = N_o e^{\frac{t ln2}{t_{1/2}}}[/tex]
so it will be
[tex]N = N_o(\frac{1}{2})^{\frac{t}{t_{1/2}}}[/tex]
now we know that
[tex]t = 1 hour[/tex]
[tex]N = \frac{N_o}{16}[/tex]
[tex]\frac{1}{16} = (\frac{1}{2})^{\frac{t}{t_{1/2}}}[/tex]
[tex]4 = \frac{1}{t_{1/2}}[/tex]
[tex]t_{1/2} = 0.25 hours[/tex]
