Respuesta :
1) Kind of motion: horizontal launch
2) Formulas:
y = yo - Vo,y * t - g*t^2 / 2
yo = 0.35 m
g = 9.8 m/s^2
Vo,y = 0 (this is the pencil does not have initial vertical speed)
The time to reach the ground does not depend on the initial horizontal speed
3) Calculations
y = 0
=> 0 = 0.35 m - 9.8 m/s^2 * t^2 / 2
=> t^2 = 0.35 m * 2 / 9.8 m/s^2 = 0.0714 s^2
=> t = √(0.0714 s^2) = 0.27 s
Answer: 0.27 s
2) Formulas:
y = yo - Vo,y * t - g*t^2 / 2
yo = 0.35 m
g = 9.8 m/s^2
Vo,y = 0 (this is the pencil does not have initial vertical speed)
The time to reach the ground does not depend on the initial horizontal speed
3) Calculations
y = 0
=> 0 = 0.35 m - 9.8 m/s^2 * t^2 / 2
=> t^2 = 0.35 m * 2 / 9.8 m/s^2 = 0.0714 s^2
=> t = √(0.0714 s^2) = 0.27 s
Answer: 0.27 s
the person above me is right i just got it right on A P E X