Respuesta :

1) Kind of motion: horizontal launch

2) Formulas:

y = yo - Vo,y * t -  g*t^2 / 2

yo = 0.35 m

g = 9.8 m/s^2

Vo,y = 0 (this is the pencil does not have initial vertical speed)

The time to reach the ground does not depend on the initial horizontal speed

3) Calculations

y = 0

=> 0 = 0.35 m - 9.8 m/s^2 * t^2 / 2

=> t^2 = 0.35 m * 2 / 9.8 m/s^2 = 0.0714 s^2

=> t = √(0.0714 s^2) = 0.27 s

Answer: 0.27 s

the person above me is right i just got it right on A P E X