Respuesta :

2 points on the line are (0,-4) and (6,0)
slope Is thus 2,/3

y= 2/3 x - 4
Answer:  " y = [tex] \frac{2}{3}[/tex] x − 4 " .

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Note:  y = mx + b ;

 b = -4  ;  

So, we have:

y = mx - 4 ;

   Given the point on the line:  " (6, 0) " ;

So, when x = 6, y = 0 .
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y = mx - 4 ;  Solve for "m" ; So we can write the equation of the line, in slope-intercept format; that is:  "y = mx + b" ;

0  = m(6) - 4 ;

Add "4" to EACH SIDE of the equation ;

0 + 4 = m(6) - 4 + 4 ;

to get:

4 = 6m ;

Divide each side of the equation by "6" ;

4/6 = 6m / 6 ; 

to get:  2/3 = m ;

Now, we can rewrite the equation:

y = mx - 4 ;

y = [tex] \frac{2}{3}[/tex] x − 4 .
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