Respuesta :
2 points on the line are (0,-4) and (6,0)
slope Is thus 2,/3
y= 2/3 x - 4
slope Is thus 2,/3
y= 2/3 x - 4
Answer: " y = [tex] \frac{2}{3}[/tex] x − 4 " .
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Note: y = mx + b ;
b = -4 ;
So, we have:
y = mx - 4 ;
Given the point on the line: " (6, 0) " ;
So, when x = 6, y = 0 .
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y = mx - 4 ; Solve for "m" ; So we can write the equation of the line, in slope-intercept format; that is: "y = mx + b" ;
0 = m(6) - 4 ;
Add "4" to EACH SIDE of the equation ;
0 + 4 = m(6) - 4 + 4 ;
to get:
4 = 6m ;
Divide each side of the equation by "6" ;
4/6 = 6m / 6 ;
to get: 2/3 = m ;
Now, we can rewrite the equation:
y = mx - 4 ;
y = [tex] \frac{2}{3}[/tex] x − 4 .
________________________________________________________
____________________________________
Note: y = mx + b ;
b = -4 ;
So, we have:
y = mx - 4 ;
Given the point on the line: " (6, 0) " ;
So, when x = 6, y = 0 .
_____________________
y = mx - 4 ; Solve for "m" ; So we can write the equation of the line, in slope-intercept format; that is: "y = mx + b" ;
0 = m(6) - 4 ;
Add "4" to EACH SIDE of the equation ;
0 + 4 = m(6) - 4 + 4 ;
to get:
4 = 6m ;
Divide each side of the equation by "6" ;
4/6 = 6m / 6 ;
to get: 2/3 = m ;
Now, we can rewrite the equation:
y = mx - 4 ;
y = [tex] \frac{2}{3}[/tex] x − 4 .
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