assuming simple interest rate with an APR, then,
[tex]\bf ~~~~~~ \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$1500\\
r=rate\to 4.25\%\to \frac{4.25}{100}\to &0.0425\\
t=years\to 18\frac{1}{2}\to &18.5
\end{cases}
\\\\\\
A=1500(1+0.0425\cdot 18.5)\implies A=1500(1.78625)[/tex]
