Write the equation of a line that is parallel to {y=0.6x+3}y=0.6x+3y, equals, 0, point, 6, x, plus, 3 and that passes through the point {(-3,-5)}(−3,−5)left parenthesis, minus, 3, comma, minus, 5, right parenthesis.
y = 0.6x - 3.2 The general form of the desired equation is y = mx + b where m = slope of the line b = y intercept of the line If two lines are parallel, their slopes will be the same, Since the slope of the given line "y = 0.6x +3" is 0.6, that will also be the slope of the desired line. So our equation becomes: y = 0.6x + b Now we can substitute the x and y value of the desired point we want the new line to pass through and find b. So y = 0.6x + b -5 = 0.6(-3) + b -5 = -1.8 + b -3.2 = b So the desired equation is now y = 0.6x - 3.2
