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2C3H8+ 702--->6CO2+8H20
FROM  Equation  above  2  moles of C3H8    reacted with  7  moles  of oxygen  to  form   6  moles of  c02 plus  8  molesof  H2O  
the  moles  of  c3H8  reacted is = MASS/ R.F.M
THE  R.F.M =48+8=44
Number  of  moles is  hence 0.025/44=5.68x10^-4
 since  ratio  of  C3H8  to   O2 is  2:7  Therefore moles of   O2  reacted  is  1.989 x10^-3
mass= r.f.m  x  number  of  moles
(1.989x10^-3)   x  32 =0.064g

Answer:

0.091

Explanation:

the balanced chemical equation for the reaction is as follows;

C₃H₈ + 5O₂ ---> 3CO₂ + 4H₂O

stoichiometry of C₃H₈ to O₂ is 1:5

number of moles of C₃H₈ reacted - 0.025 g / 44.1 g/mol = 0.000567 mol according to molar ratio of 1:5

number of O₂ moles required are 5 times the amount of C₃H₈ moles reacted therefore number of O₂ moles required - 0.000567 x 5 = 0.00284 mol .

mass of O₂ required - 0.00284 mol x 32.00 g/mol = 0.091 mol .

answer is 0.091 mol

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