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Alan sells custom made kites online. He makes a flat profit of $20 per kite, but he pays $20 per day for his website. Write an inequality that gives the number of kites Alan needs to sell to make at least $900 per week?

Respuesta :

Ivka93
To pay website Alen needs to make 1 kite a day that is 7 kites.
To earn at least 900$ per week he needs to make 900$/20$=45kites
900/20+7=52 kites. Alen need to make at least 52 kites a week to earn at least 900$.
lublana

Answer:

52 kites

Step-by-step explanation:

We are given that

Profit of one kite=$20

He pays per day for his website=$20

Number of days in 1 week=7

Allen needs to sell to make atleast in 1 week=$900

We have to write an inequality that gives the number of kites.

Let x be the number of kites.

According to question

[tex]20\times x-20\times 7 \geq 900[/tex]

[tex]20x-140 \geq 900[/tex]

adding  140 on both sides

[tex]20x+140-140\geq 900+140[/tex]

[tex]20x\geq 1040[/tex]

Divide by 20 on both sides

[tex]\frac{20x}{20}\geq \frac{1040}{20}[/tex]

[tex]x\geq 52[/tex]

[tex]x\geq 52[/tex]

Hence, Allens   need  to sell atleast 52 kites.

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