There are some nickels, dimes, and quarters in a large piggy bank. For every 2 nickels there dimes. For every 2 dimes there are 5 quarters. There are 500 coins total. a. How many nickels, dimes, and quarters are in the piggy bank? Explain your reasoning.

There are some nickels dimes and quarters in a large piggy bank For every 2 nickels there dimes For every 2 dimes there are 5 quarters There are 500 coins total class=

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Let the equation be: n + d + q = 500 let this be 1

n/2 = d/3 (for every 2 nickels there are 3 dimes) let this be 2

d/2 = q/5 (for every 2 dimes, there are 5 quarters) let this be 3

 

from 2, n = 2/3d

 

from 3, q = 5/2d

 

substitute the given values into equation 1:

 

2/3d + d + 5/2d = 500

 

Multiply by 6 both sides

 

4d + 6d + 15d = 3000

 

25d = 3000

 

d = 3000/25

 

d = 120

 

answer: 120 dimes, 2/3 x 120 = 80 nickels and 5/2 x 120 = 300 quarters.

259 nickels, 172 dimes and 69 quarters are present in the piggy bank.

According to the question, for every 2 nickels there dimes and for every 2 dimes there are 5 quarters.

[tex]2\;nickels\rightarrow 3\;dimes\\d\rightarrow \dfrac{2n}{3}[/tex]

and,

[tex]2\;dimes\rightarrow 5\;quarters\\q\rightarrow \dfrac{2d}{5}\\q\rightarrow \dfrac{4n}{15}[/tex]

And, a total number of coins in the piggy bank is 500.

So,

[tex]n+d+q=500\\n+\dfrac{2n}{3}+\dfrac{2}{5}\times \dfrac{2n}{3}=500\\\dfrac{5n}{3}+\dfrac{4n}{15}=500\\n=\dfrac{500\times 15}{25+4}\\n=\dfrac{7500}{29}\\n\approx 259[/tex]

Substitute [tex]n=\dfrac{7500}{29}[/tex] in [tex]d=\dfrac{2n}{3}[/tex],

[tex]d=\dfrac{2n}{3}\\d=\dfrac{2\times \frac{7500}{29}}{3}\\d=\dfrac{5000}{29}\\d\approx 172[/tex]

Again,

Substitute [tex]n=\dfrac{7500}{29}[/tex] in [tex]q=\dfrac{4n}{15}[/tex],

[tex]q=\dfrac{4n}{15}\\q=\dfrac{4\times \frac{7500}{29}}{15}\\q=\dfrac{2000}{29}\\q\approx 69[/tex],

Hence, 259 nickels, 172 dimes and 69 quartersare present in the piggy bank.

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