Admission to the zoo is $6 for children and $9 for adults. On a certain day, 1480 people go to the zoo and $10,500 is collected.
How many children and adults went to the zoo?
Using elimination I get:
6x + 9y = 10500
-6x-6y = -8880
Add the 2 equations and I get 3y = 1620
Divide both sides by 3 and I get y = 540
Substitute that back in to 6x+9y = 10500.
I get that 6x+9*540 = 10500
9 * 540 = 4860
Subtract 4860 from both sides and I get 6x = 5640
Divide both sides by 6 and I get x = 940
So there must have be 940 children and 540 adults
