Answer:
The width of the floor is [tex]2x^2+3x-4[/tex].
Step-by-step explanation:
It is given that the area of the rectangular floor is represented by the expression
[tex]12x^3+18x^2-24x[/tex]
The area of a rectangle is
[tex]A=length\times width[/tex]
[tex]\frac{A}{length}=width[/tex]
It is giver that the length of the floor is 6x. So, the width of the floor is
[tex]width=\frac{12x^3+18x^2-24x}{6x}[/tex]
It can be written as
[tex]width=\frac{12x^3}{6x}+\frac{18x^2}{6x}-\frac{24x}{6x}[/tex]
[tex]width=2x^2+3x-4[/tex]
Therefore the width of the floor is [tex]2x^2+3x-4[/tex].
