First, let's solve the first equation. Multiply 10 with 6 first:
6*10=60
Then subtract 5:
60-5=55
Now let's solve the second one. Multiply 5 with 10:
5*10 = 50
Then subtract the 9:
50-9=41
55 and 41 rounded to the nearest tens place are 60 and 40...but I can approximate how many times bigger one number is from the other because they're both under 100. Unless this was meant to have exponents, in which case, follow these steps:
6^10=1,000,000
1,000,000-5 = 999,995
5^10=100,000
100,000-9=99,991
In the case of exponents, 999,995 is about 10 times greater than 99,991.
I hope this answer helped you. If not, please tell me what you think of the answer. Thank you :)
