Answer:
(2.5, 2.5) and (2,0)
Step-by-step explanation:
The midsegment of △JKL that is parallel to line JL, it's a segment that begins at JK side and ends at LK side. This means we just need to find the coordinates of JK and LK midpoints.
The formula for midpoints is
[tex]m=(\frac{x_{1}+x_{2} }{2} ,\frac{y_{1}+y_{2} }{2} )[/tex]
So, for JK, points are J(1,4) and K(4,1). Replacing in the formula, we have
[tex]m_{JK} =(\frac{1+4}{2} ,\frac{4+1}{2} )\\m_{JK} =(\frac{5}{2} ,\frac{5}{2} )\\m_{JK} =(2.5 ,2.5)[/tex]
For LK, points are L(0,-1) and K(4,1)
[tex]m_{LK} =(\frac{0+4}{2} ,\frac{-1+1}{2} )\\m_{LK} =(\frac{4}{2} ,\frac{0}{2} )\\m_{LK} =(2 ,0)[/tex]
This means that the endpoint coordinates for the midsegment that is parallel to JL are (2.5, 2.5) and (2,0).
