Student tickets for the football game cost $12 each. An adult ticket costs $20. $1720 was collected for the 120 tickets sold at the last game. Which system of equations can be used to solve for the number of each kind of ticket sold?
A) x + y = 120; x + 20y = 1720

B) x + y = 120; 12x + 20y = 1720

C) x - y = 120; 12x + 20y = 1720

D) x + y = 1720; 12x - 20y = 120
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Respuesta :

The answer is B. x + y = 120; 12x + 20y = 1720

The system of equations will be:

[tex]x + y = 120 ; 12x+20y=1720[/tex]

Given:

In ticket to a football game for students is $12 and for adults is $20.

$1720 was collected for the 120 tickets sold at the last game.

To find:

The system of equations can be used to solve for the number of each kind of ticket sold.

Solution

Let the number of tickets sold to students be x

Let the number of tickets sold to adults be y

Total tickets sold = 120

[tex]x + y = 120...[1][/tex]

Cost of a ticket for a student = $12

Cost of a ticket for an adult = $20

Total amount collected from students = 12x

Total amount collected from adults = 20y

The total amount collected from the tickets = $1720

[tex]\$12x+\$20y=\$1720[/tex]

[tex]12x+20y=1720...[2][/tex]

The system of equations will be:

[tex]x + y = 120 ; 12x+20y=1720[/tex]

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