Respuesta :

s1m1
6^2. +8^2 =100=10^2
10 •500=5000ft away from home

Answer:

5000 ft.

Step-by-step explanation:

Refer the attached figure .

AC is the distance of hulk from home

Since ΔABC is right angled triangle. we will use pythagorus theorem.

[tex]Hypotenuse^{2} =Perpendicular^{2} +Base^{2}[/tex]

Hypotenuse = AC

Perpendicular = AB=6 blocks

Base = BC = 8 blocks

⇒[tex]AC^{2} =AB^{2} +BC^{2}[/tex]

⇒[tex]AC^{2} =6^{2} +8^{2}[/tex]

⇒[tex]AC^{2} =36+64[/tex]

⇒[tex]AC^{2} =100[/tex]

⇒[tex]AC =\sqrt{100}[/tex]

⇒[tex]AC =10[/tex]

Thus AC = 10 blocks .

Since we are given each block is 500 ft.

Thus 10 blocks = 500*10=5000ft.

Hence hulk is 5000 ft away from the home

Ver imagen wifilethbridge