roberto wants to display his 18 cards in an album. some pages hold 2 cards and others hold 3 cards. how many different ways can roberto display his figures?

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jazzmitchell jazzmitchell · Answer 1 · 2018-01-11T03:46:21+01:00

He could put 2 in each page 6 in two pages and 12 in 6 in another 2 in one page and 11 sets of three in the others and it just goes one

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JeanaShupp JeanaShupp · Answer 2 · 2020-03-30T04:30:15+02:00

Answer: 4

Step-by-step explanation:

Given , Roberto wants to display his 18 cards in an album. (i)

Let x= Number of pages that hold 2 cards

y= Number of pages that hold cards.

Then , total cards = 2x+3y

From (i) , we have 2x+3y=18 ... (ii)

Now , Number of different ways Roberto displays his figures =Number of possible solutions for (x,y) , where x and y are any positive integers .

At x=0 ,

[tex]3y=18\Rightarrow y=6[/tex] , i.e. (0,6) is a solution .

At y=0 ,

[tex]2x=18\Rightarrow\ x=9[/tex] , i.e. (9,0) is a solution.

At x=3 ,

[tex]2(3)+3y=18\Rightarrow\ 3y=12\Rightarrow\ y=4[/tex] , i.e. (3,4) is a solution .

At x=6 ,

[tex]2(6)+3y=18\Rightarrow\ 3y=6\Rightarrow\ y=2[/tex] , i.e. (6,2) is a solution .

Since , Number of possible solutions for (a,b) =4

Therefore, the required number of different ways can Roberto display his figure is 4.