Respuesta :
Speed is a scalar quantity given by the rate of change in distance. Thus, it is given by distance covered divided by the time taken to cover the distance.
Speed= distance/time
therefore, speed is directly proportional to the distance covered if time taken is kept constant, such that an increase in distance causes a corresponding increase in speed and vice versa, hence if the speed triples then you will need thrice times the distance to stop.
Speed= distance/time
therefore, speed is directly proportional to the distance covered if time taken is kept constant, such that an increase in distance causes a corresponding increase in speed and vice versa, hence if the speed triples then you will need thrice times the distance to stop.
Answer:
9 Times
Explanation:
The stopping distance of a car (or any traveling object) is proportional to the square of the speed of the car.
This is a consequence of the work-kinetic energy theorem, which states that the work done on the car is equal to its loss of kinetic energy:
[tex]W=K_i-K_f[/tex]
Since the final speed of the car is zero, its final kinetic energy, so we can write:
[tex]W=K_i\\Fd=\frac{1}{2}mv^2[/tex]
where
F is the force that stops the car (the force of friction)
d is the stopping distance
m is the mass of the car
v is the initial speed of the car
As we see from the equation, the stopping distance (d) depends on the square of the speed ([tex]v^2[/tex]). Therefore, it the speed is tripled, the stopping distance will acquire a factor [tex]3^2 = 9[/tex], so we will need 9 times the distance to stop.