spacehunter22
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An ellipse has an area of 4.71 in.2 and a minor axis that is 2.00 in. long. Solve for the major axis, and then sketch the ellipse using that dimension. Show only those dimensions needed for the area calculation. Note: Each grid unit = 0.25 inch.

Respuesta :

carlosego
by definition we have that the area of the ellipse is
 A = pi * a * b
 where
 a: Semi-main axis
 b: Semi-minor axis
 Substituting and clearing:
 a = A / (pi * b) = (4.71) / (PI * 1) = 1.50 in.
 Therefore the main axis is
 2 * a = 2 * (1.50) = 3in
 Graphic attached.
Ver imagen carlosego

Answer:

Step-by-step explanation:

The area of an ellipse can be calculated using:

[tex]A=\pi *a*b[/tex]

Where a is the radius of the major axis(half of the full length) and b is the radius of the minor axis(half of the full length. That means that in this case, the radius of the minor axis is half of 2, which is 1.

Substituting:

[tex]A=\pi *a*1\\4.71=\pi *a\\\frac{4.71}{\pi } =a\\a=1.5 inches\\[/tex]

The length of the secondary axis is twice the size of the radius, which makes it 3.

Ver imagen jessicapieterse

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