Respuesta :
Answers:
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Part 1) "The height of a television screen is 75% of its width. The screen is 20 inches wide. What is the area of the television screen?"
Answer: " The area of the television screen is: " 300 in² " .
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Part 2) "By percent, how does this area compare to the area of a 20-inch by 20-inch screen?
Answer: "The area of the [300 in²] television screen is "[tex] \frac{3}{16}[/tex]" % of [the area of a "20-inch by 20-in screen—which is: 400 in²] " .
{or, write as:
"The area of the [300 in²] television screen is "0.1875" % of the area of a 20-inch by 20-in screen."
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Explanation:
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Part 1) "What is the area of the television screen"?
A = L * w ;
{"Area = Length * width"} . In this case, the "height" functionss as the "length".
A = w * (0.75)w ;
A = (0.75)*w² = (0.75)*(20 in)² = (0.75)*(20)² *(in²) ;
= (0.75) (20)(20)*(in²) ;
= (0.75)*(400)*(in²) ;
= (3/4)*(400)*(in²) ;
= 300 in² .
Answer: The area of the television screen is: " 300 in² " .
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Part 2) "By percent, how does this area compare to the area of a 20-inch by 20-inch screen?"
Note: The area of a "20-inch by 20-inch screen" equals: "400 in² " .
Explanation:
Area, "A" = (20 inches)² = (20)² * (in²) = (20)*(20)*(in²) = 400 in² .
So, "300 is what percent of 400" ? (300 is from our previous solved problem)?
300 = (n/100) * 400 ;
Divide each side by 400:
300/400 = { (n/100) * 400 } / 400 ;
3/4 = (n/100) * 400 ;
↔ (n/100) * 400 = 3/4;
→ 400n / 100 = 3/4 ;
→ 4n = 3/4 ;
Multiply each side of the equation by "1/4" ;
→ (1/4) * (4n) = (3/4) *(1/4) ;
→ n = 3/16 ; or write as: 0.1875
Answer:
"The area of the [300 in²] television screen is "[tex] \frac{3}{16}[/tex]" % of the area of a 20-inch by 20-in screen."
{or, write as:
"The area of the [300 in²] television screen is "0.1875" % of the area of a 20-inch by 20-in screen."
____________________________________________________
___________________________________________________
Part 1) "The height of a television screen is 75% of its width. The screen is 20 inches wide. What is the area of the television screen?"
Answer: " The area of the television screen is: " 300 in² " .
_________________________________________________________
Part 2) "By percent, how does this area compare to the area of a 20-inch by 20-inch screen?
Answer: "The area of the [300 in²] television screen is "[tex] \frac{3}{16}[/tex]" % of [the area of a "20-inch by 20-in screen—which is: 400 in²] " .
{or, write as:
"The area of the [300 in²] television screen is "0.1875" % of the area of a 20-inch by 20-in screen."
_______________________________________________________
Explanation:
______________________________________________________
Part 1) "What is the area of the television screen"?
A = L * w ;
{"Area = Length * width"} . In this case, the "height" functionss as the "length".
A = w * (0.75)w ;
A = (0.75)*w² = (0.75)*(20 in)² = (0.75)*(20)² *(in²) ;
= (0.75) (20)(20)*(in²) ;
= (0.75)*(400)*(in²) ;
= (3/4)*(400)*(in²) ;
= 300 in² .
Answer: The area of the television screen is: " 300 in² " .
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Part 2) "By percent, how does this area compare to the area of a 20-inch by 20-inch screen?"
Note: The area of a "20-inch by 20-inch screen" equals: "400 in² " .
Explanation:
Area, "A" = (20 inches)² = (20)² * (in²) = (20)*(20)*(in²) = 400 in² .
So, "300 is what percent of 400" ? (300 is from our previous solved problem)?
300 = (n/100) * 400 ;
Divide each side by 400:
300/400 = { (n/100) * 400 } / 400 ;
3/4 = (n/100) * 400 ;
↔ (n/100) * 400 = 3/4;
→ 400n / 100 = 3/4 ;
→ 4n = 3/4 ;
Multiply each side of the equation by "1/4" ;
→ (1/4) * (4n) = (3/4) *(1/4) ;
→ n = 3/16 ; or write as: 0.1875
Answer:
"The area of the [300 in²] television screen is "[tex] \frac{3}{16}[/tex]" % of the area of a 20-inch by 20-in screen."
{or, write as:
"The area of the [300 in²] television screen is "0.1875" % of the area of a 20-inch by 20-in screen."
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