We have that
x-------------- number of problems that had been assigned the first day
problems to complete
day total
1 ------------------x---------------------------------------------------x
2------------------(x)*2----------------------------------------------2x
3------------------(x+2x)*2-----------------------------------------6x
4------------------(x+2x+6x)*2-----------------------------------18x
5------------------(x+2x+6x+18x)*2-----------------------------54x
6 -----------------(x+2x+6x+18x+54x)*2-----------------------162x
7 -----------------( x+2x+6x+18x+54x+162x)*2--------------486x
486x-162x=324x problems to resolve last day
324/486=2/3
The fraction of the problems do they still have to complete on that last day is 2/3