rainbowwedell rainbowwedell

11-01-2018
Mathematics

contestada

Solve the differential equation: dy/dx = 4y2x1/3
A. - 1/y = 3x4/3 + C/y2
B. 1/y = 3x4/3 + C
C. 1/y = 3x4/3 + C/y2
D. - 1/y = 3x4/3 + C

Respuesta :

carlosego carlosego

11-01-2018

The first thing you should do is use the method of variable separation. Then, integrate both sides to find the solution.
In this case the answer is
D. - 1/y = 3x4/3 + C
I attach the solution

Ver imagen carlosego

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