If a cube with a 5-in side length is sliced in half. What is the surface area of the two pieces?

Mr.Bloop has a cylindrical water tank on his farm. It is ten feet long and 2 feet 9 inches in diameter. Water flows out a valve in the bottom of the tank at a rate of 3.7 cubic feet per minute. At that rate, how long will it take to empty the tank when the tank is full?

Please show work!

Respuesta :

 Hello there!

1.) To start, first know that a cube has the same height, length, and width, meaning that all of the dimensions are 5-in. Then, when you slice it in half, this would mean that you have now reduced the width to half of its original. This would mean that the width is now 2.5 while the height and length remain 5.

Now that you have this information, you can now find the surface area by using this formula:

A= 2lw+2lh+2hw

Now plug in your values:

A=2(5)(2.5)+2(5)(5)+2(5)(2.5)

This would simplify to:

A=25+50+25

A=100 in squared

Therefore, the surface area of the two pieces are 100 inches squared.

2.) To start, first plug the measurements of the tank into the cylinder volume formula:

V=[tex] \pi [/tex]r^2h

V=[tex] \pi [/tex](2.75)^2(10)

V= 237.58 cubic feet

Now, we must find how long it will take the tank to empty if the rate is 3.7 cubic feet per minute so divide the volume (in feet) by the rate:

237.58/3.7= 64.2108...

Rounded to the nearest hundredth, it would take approximately 64.21 minutes to empty the take when it is full.

:)