Respuesta :

carlosego
In this case, to prove what is required, we must use the Pythagorean theorem to find the diagonal of the square.
 If the diagonal of the square is smaller than the diameter of the circle, then the square will fit perfectly in the circle without touching it.
 Diagonal = Root ((7 ^ 2) + (7 ^ 2)) = 9.89 cm.
 we observed that
 9.89cm <11cm.
 Therefore we show that:
 the square will fit inside the circle without touching the edge of the circle

The Pythagoras theorem gives the value of diagonal of the square as 9.89 cm. As the diagonal of the square is less then the diameter of the circle then conclusion can be made that the square will fit inside the circle without touching the edge of the circle.

Given information:

The diameter of the circle is 11 cm

The length of the square is 7 cm.

To show that the square will fit into the circle without touching its edge, use Pythagoras theorem to find the diagonal of the square.

If, the value of diagonal is less than the diameter of the circle then the square will fit into the circle.

So, the expression formed for the diagonal [tex]D[/tex] is,

[tex]\bold{D=\sqrt{\text{side}^2+\text{side}^2}} \\D=\sqrt{7^2+7^2} \\D=\sqrt{98}\\D=9.89[/tex]

The value of diagonal of the square is 9.89 cm.

As the diagonal of the square is less then the diameter of the circle then conclusion can be made that the square will fit inside the circle without touching the edge of the circle.

For more information, visit link:

https://brainly.com/question/343682

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