Answer:
Use law of indices to solve this
[tex]\frac{x^a}{x^b}=x^{a-b}\\\\So, \frac{(2160 x^8)}{60 x^2}=\frac{2160}{60}\times \frac{x^8}{x^2}\\\\=36x^{8-2}\\\\=36x^6\\\\ \sqrt{36x^6}=\sqrt{6x^3\times 6x^3}=6x^3[/tex]
Option C: 6 x³ , is right choice with the information given.
