Let, the number of students at Nick's school on last year be x.
Given, 98% of x is the number of students in this year.
Also given, there are 1170 students in the school this year.
First we will find 98% of x.
98% of x = [tex] (x)(\frac{98}{100}) [/tex] = [tex] \frac{98x}{100} [/tex]
So, we can write the equation as,
[tex] \frac{98x}{100} = 1170 [/tex]
To solve it for x, first we will move 100 to the other side by multiplying 100 to both sides, we will get,
[tex] (\frac{98x}{100}) (100)= (1170)(100) [/tex]
[tex] 98x = (1170)(100) [/tex]
[tex] 98x = 117000 [/tex]
To get x, we will move 98 to the right side by dividing it to both sides. We will get,
[tex] \frac{98x}{98} =\frac{117000}{98} [/tex]
[tex] x =\frac{117000}{98} [/tex]
[tex] x = 1194 [/tex] (Approximately taken to the nearest whole number)
We have got the required answer.
The number of students were there in the school last year is 1,194.
