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There are 12 members on a board of directors. if they must elect a chairperson, a secretary, and a treasurer, how many different slates of candidates are possible?

Respuesta :

12C3 = 12!/(9!)(3!) = 10 x 11 x 12 / 6 = 220.

Answer: There are 220 different possible slates of candidates.

Step-by-step explanation:

Since we have given that

Total number of members on a board of directors = 12

Number of posts to be elected = 3

As follows:

Chairperson, a secretary, and a treasurer.

So, Number of different slates of candidates that are possible is given by

[tex]^{12}C_3\\\\=\dfrac{12!}{3!(12-3)!}\\\\=\dfrac{12!}{3!}{9!}\\\\=220[/tex]

Hence, there are 220 different possible slates of candidates.

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