The solution of the student work is wrong
The remainder number should be 10
Further explanation
The division operation is one of the basic arithmetic operations
Common signs used are [tex]\boxed{:}}[/tex] or [tex]\boxed{\slash}[/tex]
The division is written by placing the numerator above the denominator with a horizontal line between them or use a slash with the numerator's position and the denominator is parallel
The division is actually an iterative subtraction operation (as many as the number of divisors)
Division is the opposite of multiplying
The general form of division can be stated by:
[tex]\large{\boxed{\bold{dividend~\div~divisor=quotient+remainder}}}[/tex]
example:
7: 3 = 2 + 1
- 7 = dividend
- 3 = divisor
- 2 = quotient
- 1 = remainder
The form of division can also be expressed in terms of fractions
In the number above, the form of fraction obtained is the form of mixed fractions
Mixed fractions consist of integers and ordinary fractions
Division operation statement:
"7 divided by 3 equals 2 remainder 1
mixed fractional form
[tex]\displaystyle {2\frac{1}{3} }[/tex]
Mixed fractions can be expressed as ordinary fractions
[tex]a\frac{b}{c}[/tex] = [tex]\frac{(c\times~a)+b}{c}[/tex]
When dividing 878 by 31, a student finds a quotient of 28 with a remainder of 11.
Division operation statement:
"878 divided by 31 equals 28 remainder 11
This division operation is declared true if the result of:
(divisor x quotient) + remainder = dividend
So from the students work above we can check:
(31x28) +11 = 878
868 + 11 = 878
879 ≠ 878
So the results of the division of tasks from students are wrong
The remainder should be 10
878- (31x28) = 10
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Keywords: division, fraction,
