Respuesta :
Answer:
14 units
Step-by-step explanation:
We are given that the area between two concentric circles is [tex]49\pi[/tex]
We have to find the length of chord in the larger circle that is tangent to the smaller circle.
Let [tex]r_1,r_2[/tex] be the radius of two circles.
[tex]r_1[/tex] be the radius of small circle and [tex]r_2[/tex] be the radius of large circle
We know that area pf circle=[tex]\pi r^2[/tex]
Area of large circle =[tex]\pi r^2_2[/tex]
Area of small circle =[tex]\pi r^2_1[/tex]
Area between two circles =[tex]49\pi[/tex]
Area of large circle -Area of small circle=[tex]49\pi[/tex]
[tex]\pi r^2_2-\pi r^2_1=49\pi[/tex]
[tex]\pi(r^2_2-r^2_1)=49[/tex]
By pythagorus theorem
[tex]AD^2=OA^2-OD^2[/tex]
[tex]AD^2=r^2_2-r^2_1[/tex]
[tex]AD=49[/tex]
[tex]AD=\sqrt{49}=7[/tex]
Length of chord=[tex]2\cdot AD[/tex]
Hence, the length of chord of the larger circle =[tex]2\cdot7=14[/tex] units
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Answer :
Length of chord is 14 units long in the larger circle that is tangent to the smaller circle.
Explanation :
Given that,
Area between a pair of concentric circles = 49π
We need to find the length of a chord in the larger circle that is tangent to the smaller circle.
Let R be the radius of larger circle.
Let r be the radius of smaller circle.
Let the length of chord be 2c
Area of space between concentric circle [tex]=\pi(R^2-r^2)[/tex]
Further Explanation:
According to question, it becomes,
[tex]\pi(R^2-r^2)=49\pi[/tex]
Therefore, [tex]R^2-r^2=49[/tex]
In ΔOAB, ∠OAB = 90° (Please find attach figure)
Using the pythagorous theorem, we get that
[tex]c=\sqrt{R^2-r^2}[/tex]
[tex]c=\sqrt{49}[/tex] [tex]\because R^2-r^2=49[/tex]
[tex]c=7[/tex]
Length of chord = 2c
Length of chord = 2(7)
= 14 units
Learn more:
https://brainly.com/question/13034352 (Answered by wagonbelleville)
Keywords :
Length of chords, Pythagorous theorem, Concentric circles
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