Answer: option A. [tex] \sqrt{11} . \sqrt{11}[/tex]
Justification:
By definition the product of the square root of a number times itself is the same number.
This is: [tex] \sqrt{n} . \sqrt{n} = n[/tex]
Because: [tex] \sqrt{n} . \sqrt{n} =( \sqrt{n})^2 = n [/tex]
Therefore, for the case given: [tex] \sqrt{11} . \sqrt{11} = 11[/tex]
And you have proved that the product of the two irrational numbers, √11, is a ratonal number, 11.
On the other hand, the other products, B, C, and D do not yield to a rational number. The result of the products shown on B, C, and D are irrational.
