Respuesta :
You can estimate the time that it will take both to mow the lawn working together by adding up the individual velocities.
The velocity of Sandra is 1 lawn / 45 minutes.
The velocity of Kelly is 1 lawn / 1 hour and 15 minures = 1 lawn / 75 minutes
The velocity together is 1 lawn / 45 minutes + 1 lawn / 75 minutes.
That sum of the fractions is:
[tex] \frac{1}{45} + \frac{1}{75} = \frac{75+45}{45*75} = \frac{120}{3375} = \frac{8}{225} [/tex]
That is velocity = 8 lawns / 225 minutes.
So, the time to mow one lawn is: t = 1lawn / velocity = [tex] \frac{1}{ \frac{8}{225} } = \frac{225}{8} = 28.125 minutes[/tex]
So, the time is about 28 minutes, which means that their estimate is longer than the time it will actually take.
The velocity of Sandra is 1 lawn / 45 minutes.
The velocity of Kelly is 1 lawn / 1 hour and 15 minures = 1 lawn / 75 minutes
The velocity together is 1 lawn / 45 minutes + 1 lawn / 75 minutes.
That sum of the fractions is:
[tex] \frac{1}{45} + \frac{1}{75} = \frac{75+45}{45*75} = \frac{120}{3375} = \frac{8}{225} [/tex]
That is velocity = 8 lawns / 225 minutes.
So, the time to mow one lawn is: t = 1lawn / velocity = [tex] \frac{1}{ \frac{8}{225} } = \frac{225}{8} = 28.125 minutes[/tex]
So, the time is about 28 minutes, which means that their estimate is longer than the time it will actually take.
Answer:
other guy tripping lol 150 million people helped
Step-by-step explanation: