At noon (12:00 p.m.), three girls began jogging from the 0 -mile mark of a trail. Each girl jogged at her own steady pace. Drag pieces of information to complete the table.

At noon 1200 pm three girls began jogging from the 0 mile mark of a trail Each girl jogged at her own steady pace Drag pieces of information to complete the tab class=

Respuesta :

Cindy: 4mph
Taylin: 4m/30 min : 8 mph
Judy:5.5m/45min : 7mph

Answer: Cyndy: speed = 4mph;

Taylin:[tex]\frac{distance}{time} = \frac{4}{\frac{1}{2} }[/tex], speed = 8mph;

Judy: [tex]\frac{distance}{time} = \frac{5\frac{1}{4} }{\frac{3}{4} }[/tex], speed=7 mph;

Step-by-step explanation: To complete the table, it has to be written the distance / time and the speed (unit rate) of each girl.

Cyndy:

For her, the first column is already given:

[tex]\frac{distance}{time}[/tex] = [tex]\frac{6}{1\frac{1}{2} }[/tex]

Speed is the distance traveled divided by how much time it was needed to walk the distance:

speed = [tex]\frac{6}{\frac{3}{2} }[/tex]

speed = 6.[tex]\frac{2}{3}[/tex]

speed = 4 miles per hour (mph)

Taylin:

[tex]\frac{distance}{time} = \frac{4}{\frac{1}{2} }[/tex]

speed = 4.2

speed = 8mph

Judy:

[tex]\frac{distance}{time} = \frac{5\frac{1}{4} }{\frac{3}{4} }[/tex]

speed = [tex]\frac{5\frac{1}{4} }{\frac{3}{4} }[/tex]

speed = [tex]\frac{\frac{21}{4} }{\frac{3}{4} }[/tex]

speed = [tex]\frac{21}{4} . \frac{4}{3}[/tex]

speed = 7mph