The functions f(x)=−[tex] \frac{3}{4} [/tex]x+2[tex] \frac{1}{4} [/tex] and g(x)=(12)x+1 are shown in the graph.

What are the solutions to −[tex] \frac{3}{4} [/tex]x+2[tex] \frac{1}{4} [/tex]=([tex] \frac{1}{2} [/tex])x+1?

Select each correct answer.


A)−1

B)0

C)1

D)2

E) 3

[Graph is included in the photo]

The functions fxtex frac34 texx2tex frac14 tex and gx12x1 are shown in the graph What are the solutions to tex frac34 texx2tex frac14 textex frac12 texx1 Select class=

Respuesta :

Answer: options A) x = -1 and C) x = 1

Explanation:

The graph show that the two functions intersect at x = - 1 and x = 1, so those are the solutions to the equality given. That is the options A) and C).

Note that the first function, [tex]f(x)=- \frac{3}{4} x+2 \frac{1}{4} = - \frac{3}{4} x+ \frac{9}{4} [/tex] is the the straight line.

The function g(x) is [tex]( \frac{1}{2}) ^x+1[/tex]

When you replace the value of x = -1 you get:

f(-1) = - (3/4) (-1) + 9/4 = 3/4 + 9/4 = 12 / 4 = 3

g(-1) = (1/2)^(-1) + 1 = 2 + 1 = 3

So, f(-1) = g(-1).

When you replace x = 1 you get:

f(1) = -(3/4)(1) + 9/4 = -3/4 + 9/4 = 6/4 = 3/2

g(1) = (1/2)^1 + 1 = 1/2 + 1 = 3/2

So, f(1) = g(1).

And in that way you have shown analiticaly that x = -1 and x = 1 are both solutions of f(x) = g(x).