Given, mass of the silicon = 6.93 g
mass of the oxygen = 7.89 g
Calculate the number of moles of both atoms:
[tex]Number of moles = \frac{given mass}{molar mass}[/tex]
Insert the given values of mass in above formula:
[tex]Number of moles of silicon = \frac{given mass of silicon in g}{molar mass of silicon}[/tex]
= [tex]\frac{6.93 g}{28 g/mol}[/tex]
= [tex]0.2475 mol[/tex]
[tex]Number of moles of oxygen = \frac{given mass of silicon in g}{molar mass of silicon}[/tex]
= [tex]\frac{7.89 g}{16 g/mol}[/tex]
= [tex]0.493125 mol[/tex]
Thus,
Total number of moles = number of silicon+ number of mole of oxygen
= [tex]0.493125 mol+0.2475 mol[/tex] =[tex]0.740625 mol[/tex]
[tex]Percentage composition = \frac{number of moles of an atom}{total number of moles of the compound}\times 100[/tex]
Put the values in above formula:
[tex]Percentage composition of silicon= \frac{number of moles of silicon}{total number of moles of the compound}\times 100[/tex]
[tex]Percentage composition of silicon= \frac{0.2475 mol}{0.740625 mol}\times 100[/tex]
= [tex]33.41 percent[/tex]
[tex]Percentage composition of oxygen= \frac{number of moles of oxygen}{total number of moles of the compound}\times 100[/tex]
[tex]Percentage composition of silicon= \frac{0.493125 mol}{0.740625 mol}\times 100[/tex]
= [tex]66. 58 percent[/tex]
Thus, percent composition of silicon and oxygen is [tex]33.41 percent[/tex]and [tex]66. 58 percent[/tex]
