35 = 5*7
7 = 5*5 -18
The dimensions of the rectangle are: length = 7 cm, width = 5 cm.
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It is handy to know your times tables.
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If you want, you can write a couple of equations and solve them.
.. L = 5W -18
.. LW = 35
Substituting for L, we have
.. (5W -18)W = 35
.. 5W^2 -18W -35 = 0 . . . . put in standard form
.. (W -5)*(5W +7) = 0 . . . . . factor
.. W = 5 or -7/5 . . . . . . . . . we are only interested in the positive solution
The width of the rectangle is 5 cm; its length is 7 cm.
