(a)
We are given
Amelia used 6 liters of gasoline to drive 48 kilometers
so, we have
6 litres = 48 kilometers
we can divide both sides by 6
[tex]\frac{6}{6} L=\frac{48}{6}km[/tex]
[tex]1 L=8km[/tex]
so, we get
[tex]rate =8km/L[/tex]
(b)
now, we have to find number of litres after 11 km
6 litres = 48 kilometers
we can also write it as
48 kilometers=6 litres
we can divide both sides by 48
[tex]\frac{48}{48}km=\frac{6}{48} L[/tex]
[tex]1km=\frac{6}{48} L[/tex]
we can multiply both sides by 11
[tex]11*1km=11*\frac{6}{48} L[/tex]
[tex]11km=\frac{11}{8} L[/tex]..................Answer
