KinG2134 KinG2134

12-02-2018
Mathematics

contestada

The length of a rectabgular field is 18 m longer than the width. the field is enclosed with fencing and divided into two parts with a fence parallel to the shorter sides. if 216 m of fencing are required what are the dimensions of the outside rectangle

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aartat23 aartat23

12-02-2018

fencing = 4x+36 + x ( parallel to width)
5x+36=216
5x=180
/5
x=36
width = 36m & length = 36+18= 54m

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