Respuesta :
f(x)=x^2-12x+20
f(x)=0
x^2-12x+20=0
Factoring:
(x-2)(x-10)=0
Two possible solutions:
x-2=0 → x=2
x-10=0 → x=10
The zeros of the polynomial function are x=2 and x=10
f(x)=0
x^2-12x+20=0
Factoring:
(x-2)(x-10)=0
Two possible solutions:
x-2=0 → x=2
x-10=0 → x=10
The zeros of the polynomial function are x=2 and x=10