The student's lab manual says to mix 50 mL of his 2.0 M CaCl2 solution with 50 mL of a 3.0 M aqueous solution of sodium carbonate(Na2CO3) a. Write a balanced equation to show the reaction. Include state symbols b. What kind of reaction is this? c. What is the limiting reagent? d. How many grams of precipitate should he get? e. If he got 8.29 of product, what is his percent yield?

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The balanced chemical reaction is [tex]CaCl_{2} + Na_{2}CO_{3}[/tex] → [tex]CaCO_{3} + 2NaCl[/tex].It is kind of double displacement reaction.

What is balanced chemical reaction?

An equation that has the same quantity of elements on both sides of the arrow has been shown to represent a balanced chemical reaction.

What is double displacement reaction.?

A class of reaction called a double displacement reaction involves the exchange of ions between two reactants to create two new molecules.

It is known that (50 ml) × (2 M [tex]CaCl_{2}[/tex]) = 100 m mol [tex]CaCl_{2}[/tex].

(50 mL ) × (3.M [tex]NaHCO_{3}[/tex] ) = 150 m Mol [tex]Na_{2}CO_{3}[/tex]

(c) It can be seen that [tex]CaCl_{2}[/tex] reacts with 100 mili moles of [tex]Na_{2}CO_{3}[/tex] but [tex]Na_{2}CO_{3}[/tex] have more amount hence, [tex]CaCl_{2}[/tex] will be limiting reagent.

(d) The amount of precipitate will be 10 g [tex]CaCO_{3}[/tex].

(100 mmol [tex]CaCl_{2}[/tex] ) × (1 mol [tex]CaCO_{3}[/tex] / 1 mol [tex]CaCl_{2}[/tex] ) × (100.875 g [tex]CaCO_{3}[/tex] /mol ) = 10 g [tex]CaCO_{3}[/tex].

(e) The percent yield will be (8.29 g / 10 g ) = 0.829 = 83 %.yield

To know more about balanced chemical reaction.

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