Respuesta :
So yeah, we'll have to use the substitution method to justify that the system of equations has no solution. We'll be substituting 3 into the second equation:
3x - 6y = -12
3x - 6y = -24
I know that this system of equations leaves us with no solution because both the x and y crosses out, leaving us with 0 = 12.
3x - 6y = -12
3x - 6y = -24
I know that this system of equations leaves us with no solution because both the x and y crosses out, leaving us with 0 = 12.
Answer:
I know I am answering 3 years late but for the people who need help, this is the answer. I know because I go to k12. And FYI I am using the substitution method so you don't need to worry about that :)
A) 3x-6y=-12
x-2y=-8
3(2y – 8) - 6y = -12
6y – 24 – 6y = -12
-24 ≠ -12
There is no solution.
B) If we were to graph them, the two lines would not intersect; they would be parallel.
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