Respuesta :

W0lf93
Charge of the glass bead Q = 8.0 x 10^-9 C Distance d = 2.0 cm = 0.02 m Coulombs constant K = 8.99 x 10^9 Nm^2/C^2 Electric Field E = k x Q / d^2 = 8.99 x 10^9 x 8.0 x 10^-9 / (0.02)^2 E = 71.92 / 0.0004 = 17.98 x 10^4 The electric field is 1.8 x 10^5 N/C
asuwafohjames

The electric field of the bead is 179800 N/C.

To calculate the electric field we use the formula below.

Formula:

  • E = kq/r².................. Equation 1

Where:

  • E = Electric field
  • r = distance of the bead from the center of the circle
  • q = Charge on the bead
  • k = constant.

From the question,

Given:

  • q = 8.0 nC = 8.0×10⁻⁹ C
  • r = 2.0 cm = 0.02 m
  • k =  8.99×10⁹ Nm²/C²

Substitute these values into equation 1

  • E = (8.0×10⁻⁹)(8.99×10⁹)/0.02²
  • E = 179800 N/C.

Hence, the electric field of the bead is 179800 N/C.

Learn more about electric field here: https://brainly.com/question/1592046


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