If the scale factor is m:n = m/n
If the length is x of the original shape, the dimensions on diagram are
[tex] \frac{m}{n} x [/tex]
If the width is y of the original shape, the dimensions on diagram are
[tex] \frac{m}{n} y [/tex]
Here the scale factor is 1/40
The dimensions of the arena hall are 200 m by 85 m.
Hence length = 200m
So length on diagram
= [tex] \frac{1}{40}200=5 [/tex]
On diagram it shall be 5 m
The width = 85 m
So width on the diagram
= [tex] \frac{1}{40} 85=2.125 [/tex]
On diagram width shall be 2.125m
The length on the diagram shall be 5 m & the width shall be 2.125 m.
