Answer:
x= -8 not extraneous.
Step-by-step explanation:
We have been given the expression:
[tex]\frac{6}{x-4}=\frac{4}{x}[/tex]
We will cross multiply the terms we get:
[tex]6x=4(x-4)[/tex]
Now, we will simplify we get:
[tex]6x=4x-16[/tex]
[tex]6x-4x=-16[/tex]
[tex]2x=-16[/tex]
[tex]x=-\frac{16}{2}[/tex]
[tex]x=-8[/tex]
Extraneous is the point which is not included in the domain of the function.
-8 is not extraneous.
Answer:
x=-8 is not extraneous.
Step-by-step explanation:
The given equation is :
[tex]\frac{6}{x-4}=\frac{4}{x}[/tex]
On cross multiplying the terms, we get
[tex]6x=4(x-4)[/tex]
⇒[tex]6x=4x-16[/tex]
⇒[tex]6x-4x=-16[/tex]
⇒[tex]2x=-16[/tex]
⇒[tex]x=\frac{-16}{2}[/tex]
⇒[tex]x=-8[/tex]
Now, Extraneous is the point which is not included in the domain of the function but x=-8 is included in the domain of the given function.
Thus, x=-8 is not extraneous.
