Suppose a 0.04-kg car traveling at 2.00 m/s can barely break an egg. What is the minimum sped a 0.08-kg car would need to have in order to break the egg?

you need more information--with what you wrote, the 0.08 kg car travelling at 1.00 m/s would have the same effect since both cars would have equal momentum, so it would need to be travelling >1.00 m/s to break the egg, assuming what you wrote is the complete problem

Answer Link

euden57 euden57 · Answer 2 · 2019-08-25T04:16:56+02:00

Answer:

V= 1m/s

Step by step Explanation:

1. The car needs a certain impulse to break the egg. The impulse is given by:

I=m. ΔV

where I is the impulse, m is the mass of the car and ΔV is the change of velocity of the car. The impulse excerted by the car of 0.04kg is:

I= (0.04kg)( 2m/s ) =0.08 kg.m/s

take into account that the change of velocity is taken as 2 m/s because the instruction says the car can "barely" break the egg, the word "barely" suggest us that after breaking it, the car stops, i.e., its final velocity is 0 m/s.

2. With this information we know that, to break an egg, we need an impulse of 0.08 kg.m/s at least.

Another car of 0.08kg could break the egg if this achieve an impulse of 0.08 kg.m/s.

Replacing in the equation of impulse, we can find the minimum speed:

0.08 kg.m/s = (0.08kg)(V)

V= 1m/s